NPNP versus coNPcoNP

OPENLandmarkOpen problemProposed c. 1971 · Standard version

Canonical statement

Is
NP≠coNP, NP\ne coNP,
where NPNP is nondeterministic polynomial time, L‾={0,1}∗∖L\overline L=\{0,1\}^*\setminus L, and coNP={L:L‾∈NP}coNP=\{L:\overline L\in NP\}?
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Is
\[
  NP\ne coNP,
\]
where \(NP\) is nondeterministic polynomial time,
\(\overline L=\{0,1\}^*\setminus L\), and
\(coNP=\{L:\overline L\in NP\}\)?

The question asks whether NPNP is closed under complementation: writing coNPcoNP for the class of languages whose complements lie in NPNP, is NP≠coNPNP\ne coNP? The problem crystallized around 1971 alongside the theory of NPNP-completeness, and no single first statement is documented. Its logical face was made precise by Cook and Reckhow, who showed that NP=coNPNP=coNP holds if and only if there is a propositional proof system in which every tautology has a polynomial-size proof [CookReckhow1979].

Since PP is closed under complementation, NP≠coNPNP\ne coNP would immediately give P≠NPP\ne NP, so the question is at least as hard as the central separation. The Cook–Reckhow correspondence launched propositional proof complexity: superpolynomial lower bounds are known for various concrete proof systems, but not for all systems simultaneously, which is what NP≠coNPNP\ne coNP demands [AroraBarak2009].

The problem is open. A resolution requires either a lower-bound technique general enough to defeat every polynomially bounded proof system, or, contrary to expectation, uniformly short certificates of unsatisfiability.

The boxed statement is the canonical open formulation — not a stronger variant or a related research program. The status reflects the catalog's last review; do your own literature search before investing serious effort.